Fix E1 -> E3,E4 typos in Serway and Jewett v8's problem 24.11.

diff --git a/latex/problems/Serway_and_Jewett_8/problem24.11.tex b/latex/problems/Serway_and_Jewett_8/problem24.11.tex
index c9109cf5b6feeb39845b8c541c7baf5836094082..0da2b88e4d45b08bc84b0c1051c4b4674da6cc18 100644 (file)
--- a/latex/problems/Serway_and_Jewett_8/problem24.11.tex
+++ b/latex/problems/Serway_and_Jewett_8/problem24.11.tex
@@ -25,8 +25,8 @@ so
   \Phi_{E1} &= \frac{-2Q + Q}{\varepsilon_0}
     = \ans{\frac{-Q}{\varepsilon_0}} \\
   \Phi_{E2} &= \frac{Q - Q}{\varepsilon_0} = \ans{0} \\
   \Phi_{E1} &= \frac{-2Q + Q}{\varepsilon_0}
     = \ans{\frac{-Q}{\varepsilon_0}} \\
   \Phi_{E2} &= \frac{Q - Q}{\varepsilon_0} = \ans{0} \\

-  \Phi_{E1} &= \frac{-2Q + Q - Q}{\varepsilon_0}
+  \Phi_{E3} &= \frac{-2Q + Q - Q}{\varepsilon_0}

     = \ans{\frac{-2Q}{\varepsilon_0}} \\
     = \ans{\frac{-2Q}{\varepsilon_0}} \\

-  \Phi_{E1} &= \frac{0}{\varepsilon_0} = \ans{0} \;.
+  \Phi_{E4} &= \frac{0}{\varepsilon_0} = \ans{0} \;.

 \end{align}
 \end{solution}
 \end{align}
 \end{solution}