1 \begin{problem*}{26.16}
2 Given a $2.50\U{$\mu$F}$ capacitor, a $6.25\U{$\mu$F}$ capacitor, and
3 a $6.00\U{V}$ battery, find the charge on each capacitor if you
4 connect them \Part{a} in series across the battery and \Part{b} in
5 parallel across the battery.
15 TwoTerminal C1 = capacitor((0,0), ang=0, "$C_1$", "2.50\U{$\mu$F}");
16 TwoTerminal C2 = capacitor(C1.end + (u,0), ang=0, "$C_2$", "6.25\U{$\mu$F}");
17 TwoTerminal B = battery("$V$", "6.00\U{V}", draw=false);
18 B.centerto(C1.beg, C2.end, offset=2u);
20 wire(B.beg, C1.beg, rlsq);
21 wire(B.end, C2.end, rlsq);
24 label("\Part{a}", B.mid + (0, -5u));
28 centerto(B, C1, offset=-2u);
30 centerto(B, C2, offset=-4u);
32 wire(B.beg, C1.beg, rlsq, dist=-u/2);
33 wire(B.beg, C2.beg, rlsq, dist=-u/2);
34 wire(B.end, C1.end, rlsq, dist=u/2);
35 wire(B.end, C2.end, rlsq, dist=u/2);
37 label("\Part{b}", B.mid + (0, -5u));
42 The net capacitance of the two capacitors in series is
44 C = \p({\frac{1}{C_1} + \frac{1}{C_2}})^{-1}
47 The equivalent capacitor has the total battery voltage across itself,
48 so it carries a charge of
50 Q = CV = 1.79\U{$\mu$F} \cdot 6.00\U{V} = \ans{10.7\U{$\mu$C}} \;.
52 Because $C_1$ and $C_2$ are in series, they each have the same $Q$ as
53 the equivalent capacitor.
56 When the capacitors are in parallel, they each have the total battery
59 Q_1 &= C_1 V = 2.50\U{$\mu$F} \cdot 6.00\U{V} = \ans{15.0\U{$\mu$C}} \\
60 Q_2 &= C_2 V = 6.25\U{$\mu$F} \cdot 6.00\U{V} = \ans{37.5\U{$\mu$C}} \;.