1 \begin{problem*}{23.12}
2 Consider the arrangement shown in Figure P23.12. Assume that $R =
3 6.00\Omega$, $l = 1.20\U{m}$, and a uniform $B=2.50\U{T}$ magnetic
4 field is directed into the page. At what speed should the bar be
5 moved to produce a current of $0.500\U{A}$ in the resistor.
9 This problem is almost identical to the recitation Problem 13.
10 Copying the induced current formula:
12 I = \frac{\varepsilon}{R} = \frac{-lvB}{R} \;,
14 where the $-$ sign indicates the current is counterclockwise (out of the
15 page), so current flows upward through the bar.
17 We can solve this equation for $v$, yeilding
19 v = \frac{IR}{lB} = \ans{1.00\U{m/s}} \;.