it is $\vect{P}_0=7.60\E{3}\jhat\U{m}$. At $t=30.0\U{s}$, the
position vector leading from you to the airplane is
$\vect{P}_{30}=(8.04\E{3}\ihat+7.60\E{3}\jhat)\U{m}$ as suggested in
-Figure P3.43. Determine the magnitude and orientation of the
+Figure~P3.43. Determine the magnitude and orientation of the
airplane's position vector at $t=45.0\U{s}$.
\begin{center}
\begin{asy}