From dfc4d0014cdc10ed9f0a1fe2ed1745ba98c7929c Mon Sep 17 00:00:00 2001
From: "W. Trevor King" <wking@tremily.us>
Date: Thu, 26 Apr 2012 15:37:23 -0400
Subject: [PATCH] Fix V_B typos in Serway and Jewett v8's 25.16 solution.

---
 latex/problems/Serway_and_Jewett_8/problem25.16.tex | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/latex/problems/Serway_and_Jewett_8/problem25.16.tex b/latex/problems/Serway_and_Jewett_8/problem25.16.tex
index f6e2fa7..c20016d 100644
--- a/latex/problems/Serway_and_Jewett_8/problem25.16.tex
+++ b/latex/problems/Serway_and_Jewett_8/problem25.16.tex
@@ -35,9 +35,9 @@ $2Q$ charge to $A$ ($\sqrt{d^2 + d^2} = \sqrt{2d^2} = d\sqrt{2}$).
 \Part{b}
 The geometry is flipped for $B$, so we have
 \begin{equation}
-  V_A = k\frac{Q}{d\sqrt{2}} + k\frac{2Q}{d}
+  V_B = k\frac{Q}{d\sqrt{2}} + k\frac{2Q}{d}
     = k\frac{Q}{d}\p({2+\frac{1}{\sqrt{2}}})
-    = \ans{6.08\E{-15}\U{V}} = \ans{6.08\U{kV}} \;,
+    = \ans{6.08\E{3}\U{V}} = \ans{6.08\U{kV}} \;,
 \end{equation}
 
 \Part{c}
-- 
2.26.2