From b0f406c6c078cf7e2192072a7261ce9740187a09 Mon Sep 17 00:00:00 2001
From: "W. Trevor King" <wking@drexel.edu>
Date: Wed, 4 Apr 2012 14:51:45 -0400
Subject: [PATCH] Add solution for Serway and Jewett v8's problem 24.11.

---
 latex/problems/Serway_and_Jewett_8/problem24.11.tex | 13 +++++++++++++
 1 file changed, 13 insertions(+)

diff --git a/latex/problems/Serway_and_Jewett_8/problem24.11.tex b/latex/problems/Serway_and_Jewett_8/problem24.11.tex
index e2b4390..c9109cf 100644
--- a/latex/problems/Serway_and_Jewett_8/problem24.11.tex
+++ b/latex/problems/Serway_and_Jewett_8/problem24.11.tex
@@ -16,4 +16,17 @@ electric flux through each surface.
 \end{problem*}
 
 \begin{solution}
+The flux through any surface is given by Gauss's law:
+\begin{equation}
+  \Phi_E = \frac{q_\text{in}}{\varepsilon_0} \;,
+\end{equation}
+so
+\begin{align}
+  \Phi_{E1} &= \frac{-2Q + Q}{\varepsilon_0}
+    = \ans{\frac{-Q}{\varepsilon_0}} \\
+  \Phi_{E2} &= \frac{Q - Q}{\varepsilon_0} = \ans{0} \\
+  \Phi_{E1} &= \frac{-2Q + Q - Q}{\varepsilon_0}
+    = \ans{\frac{-2Q}{\varepsilon_0}} \\
+  \Phi_{E1} &= \frac{0}{\varepsilon_0} = \ans{0} \;.
+\end{align}
 \end{solution}
-- 
2.26.2