From aeb4979f1ded9af83ea89805e2d90c60e31a830d Mon Sep 17 00:00:00 2001 From: "W. Trevor King" Date: Wed, 8 Jul 2009 08:29:32 -0400 Subject: [PATCH] Corrected Young and Freedman v12 23.63 solution --- latex/problems/Young_and_Freedman_12/problem23.63.tex | 5 +++-- 1 file changed, 3 insertions(+), 2 deletions(-) diff --git a/latex/problems/Young_and_Freedman_12/problem23.63.tex b/latex/problems/Young_and_Freedman_12/problem23.63.tex index 38be8d0..9e1e612 100644 --- a/latex/problems/Young_and_Freedman_12/problem23.63.tex +++ b/latex/problems/Young_and_Freedman_12/problem23.63.tex @@ -106,7 +106,8 @@ so the direction of departure is given by The total drop is a combination of the drop from the plates (calculated in \Part{c}) and the drop afterward (from simple trig) \begin{equation} - \Delta y = \Delta y_c + 12.0\E{-2}\U{m}\cdot\sin(15.4\dg) \\ - = \ans{4.01\U{cm}} + \Delta y = \Delta y_c + 12.0\E{-2}\U{m}\cdot\tan(15.4\dg) \\ + = 8.24\E{-3}\U{m} + 12.0\E{-2}\U{m}\cdot\frac{1.79}{6.50} \\ + = \ans{4.13\U{cm}} \end{equation} \end{solution} -- 2.26.2