From 79b90a86def33abb32a6a3de7ef9aa58b8dac339 Mon Sep 17 00:00:00 2001 From: "W. Trevor King" Date: Wed, 4 Apr 2012 15:25:14 -0400 Subject: [PATCH] Fix dA -> \dd A in Serway and Jewett v8's problem 24.13. --- latex/problems/Serway_and_Jewett_8/problem24.13.tex | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/latex/problems/Serway_and_Jewett_8/problem24.13.tex b/latex/problems/Serway_and_Jewett_8/problem24.13.tex index 5a83d2b..98034e8 100644 --- a/latex/problems/Serway_and_Jewett_8/problem24.13.tex +++ b/latex/problems/Serway_and_Jewett_8/problem24.13.tex @@ -12,7 +12,7 @@ Because the electric field is directed downward, there is no flux through the walls of the cylinder. All the flux crosses the cylinder at the end caps. If the area of the end cap is $A$, that flux is \begin{equation} - \Phi_E \equiv \oint_S \vect{E}\cdot\vect{dA} = E_{500}A - E_{600}A \;, + \Phi_E \equiv \oint_S \vect{E}\cdot\vect{\dd A} = E_{500}A - E_{600}A \;, \end{equation} where $E_{500}=120\U{N/C}$ and $E_{600}=100\U{N/C}$. From Gauss's law, -- 2.26.2