From: W. Trevor King <wking@drexel.edu>
Date: Thu, 12 Apr 2012 02:00:39 +0000 (-0400)
Subject: Fix begin/end problem/solution errors in some S&J v4 problems.
X-Git-Url: http://git.tremily.us/?a=commitdiff_plain;h=f95a68a5dafee9acb295179f9f60c2038c112a53;p=course.git

Fix begin/end problem/solution errors in some S&J v4 problems.
---

diff --git a/latex/problems/Serway_and_Jewett_4/problem05.34.tex b/latex/problems/Serway_and_Jewett_4/problem05.34.tex
index b3e5a00..0d95faa 100644
--- a/latex/problems/Serway_and_Jewett_4/problem05.34.tex
+++ b/latex/problems/Serway_and_Jewett_4/problem05.34.tex
@@ -21,4 +21,4 @@ So
 	= \ans{-3.596\E{6}\U{N}}
 \end{equation}
 where the $-$ sign indicates an attractive force.
-\begin{solution}
+\end{solution}
diff --git a/latex/problems/Serway_and_Jewett_4/problem05.50.tex b/latex/problems/Serway_and_Jewett_4/problem05.50.tex
index b5678da..e4949ac 100644
--- a/latex/problems/Serway_and_Jewett_4/problem05.50.tex
+++ b/latex/problems/Serway_and_Jewett_4/problem05.50.tex
@@ -10,6 +10,7 @@ tabletop revolves.  What are
  \Part{c} the speed of the puck?
 \end{problem*} % problem 5.50
 
+\begin{solution}
 \Part{a}
 Constructing a free body diagram for $m_2$, we see that the only
 forces on it are the tension \vect{T} and gravity $\vect{F}_{g2}$.
diff --git a/latex/problems/Serway_and_Jewett_4/problem19.40.tex b/latex/problems/Serway_and_Jewett_4/problem19.40.tex
index ca047a3..a3766d3 100644
--- a/latex/problems/Serway_and_Jewett_4/problem19.40.tex
+++ b/latex/problems/Serway_and_Jewett_4/problem19.40.tex
@@ -1,4 +1,4 @@
-\begin{problem}{19.40}
+\begin{problem*}{19.40}
 An insulating solid sphere of radius $a$ has a uniform volume charge
 density $\rho$ and carries a total positive charge $Q$.  A spherical
 gaussian surface of radius $r$, which shares a common center with the
diff --git a/latex/problems/Serway_and_Jewett_4/problem21.45.tex b/latex/problems/Serway_and_Jewett_4/problem21.45.tex
index 449baf8..228425d 100644
--- a/latex/problems/Serway_and_Jewett_4/problem21.45.tex
+++ b/latex/problems/Serway_and_Jewett_4/problem21.45.tex
@@ -109,4 +109,4 @@ So using $V_c' = V_c/10$ we have
  \ln(10) &= \frac{t}{RC} \\
  t &= RC\ln(10) = \ans{8.29\U{$\mu$s}}
 \end{align}
-\ens{solution}
+\end{solution}