From: Junio C Hamano Date: Fri, 23 Mar 2007 20:34:49 +0000 (-0700) Subject: Fix path-limited "rev-list --bisect" termination condition. X-Git-Tag: v1.5.1-rc2~21 X-Git-Url: http://git.tremily.us/?a=commitdiff_plain;h=a4e9d71edb5f87b4dae57b8a474124451e397e6c;p=git.git Fix path-limited "rev-list --bisect" termination condition. In a path-limited bisection, when the $bad commit is not changing the limited path, and the number of suspects is 1, the code miscounted and returned $bad from find_bisection(), which is not marked with TREECHANGE. This is of course filtered by the output routine, resulting in an empty output, in turn causing git-bisect driver to say "$bad was both good and bad". Illustration. Suppose you have these four commits, and only C changes path P. You know D is bad and A is good. A---B---C*--D git-bisect driver runs this to find a bisection point: $ git rev-list --bisect A..D -- P which calls find_bisection() with B, C and D. The set of commits that is given to this function is the same set of commits as rev-list without --bisect option and pathspec returns. Among them, only C is marked with TREECHANGE. Let's call the set of commits given to find_bisection() that are marked with TREECHANGE (or all of them if no path limiter is in effect) "the bisect set". In the above example, the size of the bisect set is 1 (contains only "C"). For each commit in its input, find_bisection() computes the number of commits it can reach in the bisect set. For a commit in the bisect set, this number includes itself, so the number is 1 or more. This number is called "depth", and computed by count_distance() function. When you have a bisect set of N commits, and a commit has depth D, how good is your bisection if you returned that commit? How good this bisection is can be measured by how many commits are effectively tested "together" by testing one commit. Currently you have (N-1) untested commits (the tip of the bisect set, although it is included in the bisect set, is already known to be bad). If the commit with depth D turns out to be bad, then your next bisect set will have D commits and you will have (D-1) untested commits left, which means you tested (N-1)-(D-1) = (N-D) commits with this bisection. If it turns out to be good, then your next bisect set will have (N-D) commits, and you will have (N-D-1) untested commits left, which means you tested (N-1)-(N-D-1) = D commits with this bisection. Therefore, the goodness of this bisection is is min(N-D, D), and find_bisection() function tries to find a commit that maximizes this, by initializing "closest" variable to 0 and whenever a commit with the goodness that is larger than the current "closest" is found, that commit and its goodness are remembered by updating "closest" variable. The "the commit with the best goodness so far" is kept in "best" variable, and is initialized to a commit that happens to be at the beginning of the list of commits given to this function (which may or may not be in the bisect set when path-limit is in use). However, when N is 1, then the sole tree-changing commit has depth of 1, and min(N-D, D) evaluates to 0. This is not larger than the initial value of "closest", and the "so far the best one" commit is never replaced in the loop. When path-limit is not in use, this is not a problem, as any commit in the input set is tree-changing. But when path-limit is in use, and when the starting "bad" commit does not change the specified path, it is not correct to return it. Signed-off-by: Junio C Hamano --- diff --git a/builtin-rev-list.c b/builtin-rev-list.c index c2db5a5b0..51858e323 100644 --- a/builtin-rev-list.c +++ b/builtin-rev-list.c @@ -180,7 +180,7 @@ static struct commit_list *find_bisection(struct commit_list *list) nr++; p = p->next; } - closest = 0; + closest = -1; best = list; for (p = list; p; p = p->next) {