Fix begin/end problem/solution errors in some S&J v4 problems.

diff --git a/latex/problems/Serway_and_Jewett_4/problem05.34.tex b/latex/problems/Serway_and_Jewett_4/problem05.34.tex
index b3e5a00ef3f48cc19c255a42b72426b241a70925..0d95faac564dd48be73c076e7b5041349b1a881a 100644 (file)
--- a/latex/problems/Serway_and_Jewett_4/problem05.34.tex
+++ b/latex/problems/Serway_and_Jewett_4/problem05.34.tex
@@ -21,4 +21,4 @@ So
        = \ans{-3.596\E{6}\U{N}}
 \end{equation}
 where the $-$ sign indicates an attractive force.
-\begin{solution}
+\end{solution}

diff --git a/latex/problems/Serway_and_Jewett_4/problem05.50.tex b/latex/problems/Serway_and_Jewett_4/problem05.50.tex
index b5678daeeb7210408bab5ed01da6fc85da4087c6..e4949ace1cfb68ce4f5e4f4dd03eacffe671ebfa 100644 (file)
--- a/latex/problems/Serway_and_Jewett_4/problem05.50.tex
+++ b/latex/problems/Serway_and_Jewett_4/problem05.50.tex
@@ -10,6 +10,7 @@ tabletop revolves.  What are
  \Part{c} the speed of the puck?
 \end{problem*} % problem 5.50
 
+\begin{solution}
 \Part{a}
 Constructing a free body diagram for $m_2$, we see that the only
 forces on it are the tension \vect{T} and gravity $\vect{F}_{g2}$.

diff --git a/latex/problems/Serway_and_Jewett_4/problem19.40.tex b/latex/problems/Serway_and_Jewett_4/problem19.40.tex
index ca047a3c1f2cc398725bdcae7be4e9b1faaa0c17..a3766d3e268e00c49c49910e108f47d9143d9de5 100644 (file)
--- a/latex/problems/Serway_and_Jewett_4/problem19.40.tex
+++ b/latex/problems/Serway_and_Jewett_4/problem19.40.tex
@@ -1,4 +1,4 @@
-\begin{problem}{19.40}
+\begin{problem*}{19.40}
 An insulating solid sphere of radius $a$ has a uniform volume charge
 density $\rho$ and carries a total positive charge $Q$.  A spherical
 gaussian surface of radius $r$, which shares a common center with the

diff --git a/latex/problems/Serway_and_Jewett_4/problem21.45.tex b/latex/problems/Serway_and_Jewett_4/problem21.45.tex
index 449baf881adbd4da4189f37c239ae6f34af2189a..228425d7e7857841ce2ab3ecbe3317b6db65a170 100644 (file)
--- a/latex/problems/Serway_and_Jewett_4/problem21.45.tex
+++ b/latex/problems/Serway_and_Jewett_4/problem21.45.tex
@@ -109,4 +109,4 @@ So using $V_c' = V_c/10$ we have
  \ln(10) &= \frac{t}{RC} \\
  t &= RC\ln(10) = \ans{8.29\U{$\mu$s}}
 \end{align}
-\ens{solution}
+\end{solution}