# are given the same value (in sorting, for example).
if len(vlist1) <= i or len(vlist1[i]) == 0:
list1.append(-1)
- list2.append(string.atoi(vlist2[i]))
+ list2.append(int(vlist2[i]))
elif len(vlist2) <= i or len(vlist2[i]) == 0:
- list1.append(string.atoi(vlist1[i]))
+ list1.append(int(vlist1[i]))
list2.append(-1)
# Let's make life easy and use integers unless we're forced to use floats
elif (vlist1[i][0] != "0" and vlist2[i][0] != "0"):
- list1.append(string.atoi(vlist1[i]))
- list2.append(string.atoi(vlist2[i]))
+ list1.append(int(vlist1[i]))
+ list2.append(int(vlist2[i]))
# now we have to use floats so 1.02 compares correctly against 1.1
else:
list1.append(string.atof("0."+vlist1[i]))
if s1[1] != s2[1]:
# it's possible that the s(1|2)[1] == ''
# in such a case, fudge it.
- try: r1 = string.atoi(s1[1])
+ try: r1 = int(s1[1])
except ValueError: r1 = 0
- try: r2 = string.atoi(s2[1])
+ try: r2 = int(s2[1])
except ValueError: r2 = 0
return r1 - r2
# the suffix part is equal to, so finally check the revision
if match1.group(10):
- r1 = string.atoi(match1.group(10))
+ r1 = int(match1.group(10))
else:
r1 = 0
if match2.group(10):
- r2 = string.atoi(match2.group(10))
+ r2 = int(match2.group(10))
else:
r2 = 0
vercmp_cache[mykey] = r1 - r2
myrev=myparts[-1]
if len(myrev) and myrev[0]=="r":
try:
- string.atoi(myrev[1:])
+ int(myrev[1:])
revok=1
- except:
+ except ValueError:
pass
if revok:
verPos = -2