return 0;
}
+/*
+ * When there is no known charset, guess.
+ *
+ * Right now we assume that if the target is UTF-8 (the default),
+ * and it already looks like UTF-8 (which includes US-ASCII as its
+ * subset, of course) then that is what it is and there is nothing
+ * to do.
+ *
+ * Otherwise, we default to assuming it is Latin1 for historical
+ * reasons.
+ */
+static const char *guess_charset(const char *line, const char *target_charset)
+{
+ if (is_encoding_utf8(target_charset)) {
+ if (is_utf8(line))
+ return NULL;
+ }
+ return "latin1";
+}
+
static void convert_to_utf8(char *line, const char *charset)
{
- static const char latin_one[] = "latin1";
- const char *input_charset = *charset ? charset : latin_one;
- char *out = reencode_string(line, metainfo_charset, input_charset);
+ char *out;
+
+ if (!charset || !*charset) {
+ charset = guess_charset(line, metainfo_charset);
+ if (!charset)
+ return;
+ }
+ out = reencode_string(line, metainfo_charset, charset);
if (!out)
die("cannot convert from %s to %s\n",
- input_charset, metainfo_charset);
+ charset, metainfo_charset);
strcpy(line, out);
free(out);
}