Corrected Young and Freedman v12 23.63 solution

diff --git a/latex/problems/Young_and_Freedman_12/problem23.63.tex b/latex/problems/Young_and_Freedman_12/problem23.63.tex
index 38be8d07786f948d277621f0ddfea283275ae006..9e1e61263313eb7910b5fc1b8b28898f8c1aa34e 100644 (file)
--- a/latex/problems/Young_and_Freedman_12/problem23.63.tex
+++ b/latex/problems/Young_and_Freedman_12/problem23.63.tex
@@ -106,7 +106,8 @@ so the direction of departure is given by
 The total drop is a combination of the drop from the plates
 (calculated in \Part{c}) and the drop afterward (from simple trig)
 \begin{equation}
-  \Delta y = \Delta y_c + 12.0\E{-2}\U{m}\cdot\sin(15.4\dg) \\
-    = \ans{4.01\U{cm}}
+  \Delta y = \Delta y_c + 12.0\E{-2}\U{m}\cdot\tan(15.4\dg) \\
+    = 8.24\E{-3}\U{m} + 12.0\E{-2}\U{m}\cdot\frac{1.79}{6.50} \\
+    = \ans{4.13\U{cm}}
 \end{equation}
 \end{solution}