Fix e -> \E exponent typo in Serway and Jewett v8's problem 23.15.
authorW. Trevor King <wking@drexel.edu>
Thu, 5 Apr 2012 05:26:56 +0000 (01:26 -0400)
committerW. Trevor King <wking@drexel.edu>
Thu, 5 Apr 2012 05:26:56 +0000 (01:26 -0400)
latex/problems/Serway_and_Jewett_8/problem23.15.tex

index 1f3261782257904bde8af9c1006f30b3c66c6000..6d2ec6315a206c5f3f03d12bcaff37f9bbfd5386 100644 (file)
@@ -11,7 +11,8 @@ electron?
 \Part{a}
 \begin{equation}
   F = k\frac{q_1q_2}{r^2}
-    = 8.99\E{9}\U{Nm$^2$/C$^2$}\frac{(1.60e-19\U{C})^2}{(5.29\E{-11}\U{m})^2}
+    = 8.99\E{9}\U{Nm$^2$/C$^2$}
+      \frac{(1.60\E{-19}\U{C})^2}{(5.29\E{-11}\U{m})^2}
     = \ans{8.22\E{-8}\U{N}}
 \end{equation}