Since it doesn't actually touch its argument, this makes
sense.
However, we still want to return a non-const version (which
requires a cast) so that this:
struct ref *a, *b;
a = find_ref_by_name(b);
works. Unfortunately, you can also silently strip the const
from a variable:
struct ref *a;
const struct ref *b;
a = find_ref_by_name(b);
This is a classic C const problem because there is no way to
say "return the type with the same constness that was passed
to us"; we provide the same semantics as standard library
functions like strchr.
Signed-off-by: Jeff King <peff@peff.net>
Signed-off-by: Jay Soffian <jaysoffian@gmail.com>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
#define REF_HEADS (1u << 1)
#define REF_TAGS (1u << 2)
-extern struct ref *find_ref_by_name(struct ref *list, const char *name);
+extern struct ref *find_ref_by_name(const struct ref *list, const char *name);
#define CONNECT_VERBOSE (1u << 0)
extern struct child_process *git_connect(int fd[2], const char *url, const char *prog, int flags);
return 0;
}
-struct ref *find_ref_by_name(struct ref *list, const char *name)
+struct ref *find_ref_by_name(const struct ref *list, const char *name)
{
for ( ; list; list = list->next)
if (!strcmp(list->name, name))
- return list;
+ return (struct ref *)list;
return NULL;
}