remote-curl: accept empty line as terminator
authorSverre Rabbelier <srabbelier@gmail.com>
Sat, 16 Jul 2011 13:03:29 +0000 (15:03 +0200)
committerJunio C Hamano <gitster@pobox.com>
Tue, 19 Jul 2011 18:17:47 +0000 (11:17 -0700)
This went unnoticed because the transport helper infrastructore did
not check the return value of the helper, nor did the helper print
anything before exiting.

While at it also make sure that the stream doesn't end unexpectedly.

Signed-off-by: Sverre Rabbelier <srabbelier@gmail.com>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
remote-curl.c

index 17d8a9b377265aeed9765f04d505959e1f7fb9b0..7b3c113b0965d86ba8866741b4b3f238d319bfe0 100644 (file)
@@ -855,7 +855,14 @@ int main(int argc, const char **argv)
        http_init(remote);
 
        do {
-               if (strbuf_getline(&buf, stdin, '\n') == EOF)
+               if (strbuf_getline(&buf, stdin, '\n') == EOF) {
+                       if (ferror(stdin))
+                               fprintf(stderr, "Error reading command stream\n");
+                       else
+                               fprintf(stderr, "Unexpected end of command stream\n");
+                       return 1;
+               }
+               if (buf.len == 0)
                        break;
                if (!prefixcmp(buf.buf, "fetch ")) {
                        if (nongit)
@@ -895,6 +902,7 @@ int main(int argc, const char **argv)
                        printf("\n");
                        fflush(stdout);
                } else {
+                       fprintf(stderr, "Unknown command '%s'\n", buf.buf);
                        return 1;
                }
                strbuf_reset(&buf);