\section{Single-domain proteins under constant loading}
-eq:sawsim:order-dep
+TODO: consolidate with \cref{sec:sawsim:results:scaffold}.
-Let $x$ be the end to end distance of the protein, $t$ be the time since loading began, $F$ be tension applied to the protein, $P$ be the surviving population of folded proteins.
-Make the definitions
+Let $x$ be the end to end distance of the protein, $t$ be the time
+since loading began, $F$ be tension applied to the protein, $N_f$ be
+the surviving population of folded proteins. Make the definitions
\begin{align}
v &\equiv \deriv{t}{x} && \text{the pulling velocity} \\
- k &\equiv \deriv{x}{F} && \text{the loading spring constant} \\
- P_0 &\equiv P(t=0) && \text{the initial number of folded proteins} \\
- D &\equiv P_0 - P && \text{the number of dead (unfolded) proteins} \\
- \kappa &\equiv -\frac{1}{P} \deriv{t}{P} && \text{the unfolding rate}
+ \kappa &\equiv \deriv{x}{F} && \text{the loading spring constant} \\
+ N_{f0} &\equiv N_f(t=0) && \text{the initial number of folded proteins} \\
+ N_u &\equiv N_{f0} - N_f && \text{the number of unfolded proteins} \\
+ k_u &\equiv -\frac{1}{N_f} \deriv{t}{N_f} && \text{the unfolding rate}
\end{align}
\nomenclature{$\equiv$}{Defined as (\ie\ equivalent to)}
The proteins are under constant loading because
\begin{equation}
- \deriv{t}{F} = \deriv{x}{F}\deriv{t}{x} = kv\;,
+ \deriv{t}{F} = \deriv{x}{F}\deriv{t}{x} = \kappa v\;,
\end{equation}
-a constant, since both $k$ and $v$ are constant (\citet{evans97} in the text on the first page, \citet{dudko06} in the text just before Eqn.~4).
-
-The instantaneous likelyhood of a protein unfolding is given by $\deriv{F}{D}$, and the unfolding histogram is merely this function discretized over a bin of width $W$(This is similar to \citet{dudko06} Eqn.~2, remembering that $\dot{F}=kv$, that their probability density is not a histogram ($W=1$), and that their pdf is normalized to $N=1$).
+a constant, since both $\kappa$ and $v$ are constant (\citet{evans97}
+in the text on the first page, \citet{dudko06} in the text just before
+\fref{equation}{4}).
+
+The instantaneous likelyhood of a protein unfolding is given by
+$\deriv{F}{N_u}$, and the unfolding histogram is merely this function
+discretized over a bin of width $W$ (This is similar to
+\xref{dudko06}{equation}{2}, remembering that $\dot{F}=\kappa v$, that
+their probability density is not a histogram ($W=1$), and that their
+probability density function is normalized to $N=1$).
\begin{equation}
h(F) \equiv \deriv{\text{bin}}{F}
- = \deriv{F}{D} \cdot \deriv{\text{bin}}{F}
- = W \deriv{F}{D}
- = -W \deriv{F}{P}
- = -W \deriv{t}{P} \deriv{F}{t}
- = \frac{W}{vk} P\kappa \label{eq:unfold:hist}
+ = \deriv{F}{N_u} \cdot \deriv{\text{bin}}{F}
+ = W \deriv{F}{N_u}
+ = -W \deriv{F}{N_f}
+ = -W \deriv{t}{N_f} \deriv{F}{t}
+ = \frac{W}{vk} N_f\kappa \label{eq:unfold:hist}
\end{equation}
-Solving for theoretical histograms is merely a question of taking your chosen $\kappa$, solving for $P(f)$, and plugging into Eqn. \ref{eq:unfold:hist}.
-We can also make a bit of progress solving for $P$ in terms of $\kappa$ as follows:
+Solving for theoretical histograms is merely a question of taking your
+chosen $k_u$, solving for $N_f(f)$, and plugging into
+\cref{eq:unfold:hist}. We can also make a bit of progress solving for
+$N_f$ in terms of $k_u$ as follows:
\begin{align}
- \kappa &\equiv -\frac{1}{P} \deriv{t}{P} \\
- -\kappa \dd t \cdot \deriv{t}{F} &= \frac{\dd P}{P} \\
- \frac{-1}{kv} \int \kappa \dd F &= \ln(P) + c \\
- P &= C\exp{\p({\frac{-1}{kv}\integral{}{}{F}{\kappa}})} \;, \label{eq:P}
+ k_u &\equiv -\frac{1}{N_f} \deriv{t}{N_f} \\
+ -k_u \dd t \cdot \deriv{t}{F} &= \frac{\dd N_f}{N_f} \\
+ \frac{-1}{\kappa v} \int k_0 \dd F &= \ln(N_f) + c \\
+ N_f &= C\exp{\p({\frac{-1}{\kappa v}\integral{}{}{F}{k_u}})} \;,
+ \label{eq:N_f}
\end{align}
-where $c \equiv \ln(C)$ is a constant of integration scaling $P$.
+where $c \equiv \ln(C)$ is a constant of integration scaling $N_f$.
\subsection{Constant unfolding rate}