1 \begin{problem*}{22.16}
2 A wire $l = 2.80\U{m}$ in length carries a current of $I = 5.00\U{A}$
3 in a region where a uniform magnetic field has a magnitude of $B =
4 0.390\U{T}$. Calculate the magnitude of the magnetic force on the
5 wire assuming that the angle between the magnetic field and the
7 \Part{a} $\theta_a = 60.0\dg$,
8 \Part{b} $\theta_b = 90.0\dg$, and
9 \Part{c} $\theta_c = 120\dg$.
10 \end{problem*} % problem 22.16
13 Using our formula for the force on a wire due to a uniform field we
16 \vect{F} &= I\vect{l}\times\vect{B} \\
17 F &= IlB\sin\theta \;,
21 F_a &= IlB\sin\theta_a = \ans{4.73\U{N}}\\
22 F_b &= IlB\sin\theta_b = \ans{5.46\U{N}}\\
23 F_c &= IlB\sin\theta_c = \ans{4.73\U{N}} \;.